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First derivative reconstruction results

The first derivative of the function

$\begin{displaymath} \mathrm{f}(x)=-\frac{1}{3}x^4 + \frac{1}{2}x^3 - 3x \end{displaymath}$

which is definitely

$\begin{displaymath} \mathrm{f}\,'(x)=-\frac{4}{3}x^3 + \frac{3}{2}x^2 - 3 \end{displaymath}$

was sampled on integer positions and reconstructed with the methods discussed in Chapter 5. The results are depicted on the following pages, more about the experiment itself can be found in Sec. 5.1.4.

$\includegraphics[angle=-90,width=10cm]{picsChaDerivativeReco/cent_diff_analytic.ps}$

$\includegraphics[angle=-90,width=10cm]{picsChaDerivativeReco/cardinal_cubics.ps}$

$\includegraphics[angle=-90,width=10cm]{picsChaDerivativeReco/Rect.ps}$

$\includegraphics[angle=-90,width=10cm]{picsChaDerivativeReco/Bartlett.ps}$

$\includegraphics[angle=-90,width=10cm]{picsChaDerivativeReco/Welch.ps}$

$\includegraphics[angle=-90,width=10cm]{picsChaDerivativeReco/Parzen.ps}$

$\includegraphics[angle=-90,width=10cm]{picsChaDerivativeReco/Hann.ps}$

$\includegraphics[angle=-90,width=10cm]{picsChaDerivativeReco/Hamming.ps}$

$\includegraphics[angle=-90,width=10cm]{picsChaDerivativeReco/Blackman.ps}$

$\includegraphics[angle=-90,width=10cm]{picsChaDerivativeReco/Lanczos.ps}$

$\includegraphics[angle=-90,width=10cm]{picsChaDerivativeReco/Kaiser2.ps}$

$\includegraphics[angle=-90,width=10cm]{picsChaDerivativeReco/Kaiser3.ps}$

$\includegraphics[angle=-90,width=10cm]{picsChaDerivativeReco/Gauss2.ps}$

$\includegraphics[angle=-90,width=10cm]{picsChaDerivativeReco/Gauss3.ps}$

1999-12-29